A mixture of n1 moles of monoatomic gas and n2 moles of diatomic gas has γ =1.5 . Than :-

Question

A mixture of n1 moles of monoatomic gas and n2 moles of diatomic gas has &gamma; =1.5 . Than :- (A) n1=n2 (B) 2n1=n2 (C) n1=2n2 (D) n1=3n2

Tardigrade Admin · Accepted Answer

&gamma; =(n1 C p2 + n2 C p2/n1 C v1 + n2 C v2) ⇒ 1.5=(n1 (5/2) R + n2 (7/2) R/n1 (3 R)2 + n2 (5 R)2 ⇒ 1.5=(5 n1 + 7 n2/3 n1 + 5 n2)=(3/2) ⇒ 10n/1)+14n2=9n1+15n2 n1=n2

Q. A mixture of $n_{1}$ moles of monoatomic gas and $n_{2}$ moles of diatomic gas has $γ = 1.5$ . Than :-

$n_{1} = n_{2}$

$2 n_{1} = n_{2}$

$n_{1} = 2 n_{2}$

$n_{1} = 3 n_{2}$

Q. A mixture of n1​ moles of monoatomic gas and n2​ moles of diatomic gas has γ=1.5 . Than :-

n1​=n2​

2n1​=n2​

n1​=2n2​

n1​=3n2​

γ=n1​Cv1​+n2​Cv2​n1​Cp2​+n2​Cp2​​ ⇒1.5=n1​23R​+n2​25R​n1​25​R+n2​27​R​ ⇒1.5=3n1​+5n2​5n1​+7n2​​=23​ ⇒10n1​+14n2​=9n1​+15n2​ n1​=n2​

Q. A mixture of $n_{1}$ moles of monoatomic gas and $n_{2}$ moles of diatomic gas has $γ = 1.5$ . Than :-

$n_{1} = n_{2}$

$2 n_{1} = n_{2}$

$n_{1} = 2 n_{2}$

$n_{1} = 3 n_{2}$