A mixture of hydrogen and oxygen contains 40 % hydrogen by mass when the pressure is 2.2 bar. The partial pressure of hydrogen is bar. (Nearest Integer)

Question

A mixture of hydrogen and oxygen contains 40 % hydrogen by mass when the pressure is 2.2 bar. The partial pressure of hydrogen is bar. (Nearest Integer) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Let W H 2=40 g ⇒ n H 2=(40/2)=20 W O 2=60 g ⇒ n O 2=(60/32)=(15/8) P H 2=((20/20+(15)8)) × 2.2 =(20/20+1.875) × 2.2 =(20/21.875) × 2.2 =2.0114 ≃ 2.01 bar

Q. A mixture of hydrogen and oxygen contains $40%$ hydrogen by mass when the pressure is $2.2$ bar. The partial pressure of hydrogen is bar. (Nearest Integer)

Let $W_{H_{2}} = 40 g \Rightarrow n_{H_{2}} = \frac{40}{2} = 20$
$W_{O_{2}} = 60 g \Rightarrow n_{O_{2}} = \frac{60}{32} = \frac{15}{8}$
$P_{H_{2}} = (\frac{20}{20 + \frac{15}{8}}) \times 2.2$
$= \frac{20}{20 + 1.875} \times 2.2$
$= \frac{20}{21.875} \times 2.2$
$= 2.0114$
$≃ 2.01 ba r$

Q. A mixture of hydrogen and oxygen contains 40% hydrogen by mass when the pressure is 2.2 bar. The partial pressure of hydrogen is bar. (Nearest Integer)

Let WH2​​=40g⇒nH2​​=240​=20 WO2​​=60g⇒nO2​​=3260​=815​ PH2​​=(20+815​20​)×2.2 =20+1.87520​×2.2 =21.87520​×2.2 =2.0114 ≃2.01bar

Q. A mixture of hydrogen and oxygen contains $40%$ hydrogen by mass when the pressure is $2.2$ bar. The partial pressure of hydrogen is bar. (Nearest Integer)

Let $W_{H_{2}} = 40 g \Rightarrow n_{H_{2}} = \frac{40}{2} = 20$
$W_{O_{2}} = 60 g \Rightarrow n_{O_{2}} = \frac{60}{32} = \frac{15}{8}$
$P_{H_{2}} = (\frac{20}{20 + \frac{15}{8}}) \times 2.2$
$= \frac{20}{20 + 1.875} \times 2.2$
$= \frac{20}{21.875} \times 2.2$
$= 2.0114$
$≃ 2.01 ba r$