A mixture of 2.3 g formic acid and 4.5 g oxalic acid is treated with cone. H2SO4. The evolved gaseous mixture is passed through KOH pellets. Weight (in g ) of the remaining product at STP will be

Question

A mixture of 2.3 g formic acid and 4.5 g oxalic acid is treated with cone. H2SO4. The evolved gaseous mixture is passed through KOH pellets. Weight (in g ) of the remaining product at STP will be (A) 4.4 (B) 1.4 (C) 2.8 (D) 3.0

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/b8cf73cd881101b316e1cc96fd359c0e-.png" /> Gaseous mixture formed is CO and CO 2 when it is passed through KOH, only CO 2 is absorbed. So the remaining gas is CO. So, weight of remaining gaseous product CO is (2/20) × 28=2.8 g

Q. A mixture of $2.3 g$ formic acid and $4.5 g$ oxalic acid is treated with cone. $H_{2} S O_{4}$ . The evolved gaseous mixture is passed through $K O H$ pellets. Weight (in $g$ ) of the remaining product at $STP$ will be

4.4

1.4

2.8

3.0

Gaseous mixture formed is $CO$ and $C O_{2}$ when it is passed through $K O H$ , only $C O_{2}$ is absorbed. So the remaining gas is $CO$ .

So, weight of remaining gaseous product $CO$ is

$\frac{2}{20} \times 28 = 2.8 g$

Q. A mixture of 2.3g formic acid and 4.5g oxalic acid is treated with cone. H2​SO4​. The evolved gaseous mixture is passed through KOH pellets. Weight (in g ) of the remaining product at STP will be

4.4

1.4

2.8

3.0

Gaseous mixture formed is CO and CO2​ when it is passed through KOH, only CO2​ is absorbed. So the remaining gas is CO. So, weight of remaining gaseous product CO is 202​×28=2.8g

Q. A mixture of $2.3 g$ formic acid and $4.5 g$ oxalic acid is treated with cone. $H_{2} S O_{4}$ . The evolved gaseous mixture is passed through $K O H$ pellets. Weight (in $g$ ) of the remaining product at $STP$ will be

Gaseous mixture formed is $CO$ and $C O_{2}$ when it is passed through $K O H$ , only $C O_{2}$ is absorbed. So the remaining gas is $CO$ .

So, weight of remaining gaseous product $CO$ is

$\frac{2}{20} \times 28 = 2.8 g$