A mixture of 100 m mol of Ca(OH)2 and 2 g of sodium sulphate was dissolved in water and the volume was made up to 100 mL. The mass of calcium sulphate formed and the concentration of OH- in resulting solution, respectively, are: (Molar mass of Ca(OH)2, Na2SO4 and CaSO4 are 74, 143 and 136 g mol-1, respectively; Ksp of Ca(OH)2 is 5.5 × 10-6)

Question

A mixture of 100 m mol of Ca(OH)2 and 2 g of sodium sulphate was dissolved in water and the volume was made up to 100 mL. The mass of calcium sulphate formed and the concentration of OH- in resulting solution, respectively, are: (Molar mass of Ca(OH)2, Na2SO4 and CaSO4 are 74, 143 and 136 g mol-1, respectively; Ksp of Ca(OH)2 is 5.5 × 10-6) (A) 1.9 g, 0.14 mol L-1 (B) 13.6 g, 0.14 mol L-1 (C) 1.9 g, 0.28 mol L-1 (D) 13.6 g, 0.28 mol L-1

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/8034bf1eee9df05713b7c2d0f96508df-.png" /> wCaSO4 = 14 ×10-3 ×136 = 1.9 gm [OH-] = (28/100) = 0.28 M

$1.9 g, 0.14 m o l L^{- 1}$

$13.6 g, 0.14 m o l L^{- 1}$

$1.9 g, 0.28 m o l L^{- 1}$

$13.6 g, 0.28 m o l L^{- 1}$

$w_{C a S O_{4}} = 14 \times 1 0^{- 3} \times 136 = 1.9 g m$
$[O H^{-}] = \frac{28}{100} = 0.28 M$

1.9g,0.14molL−1

13.6g,0.14molL−1

1.9g,0.28molL−1

13.6g,0.28molL−1

wCaSO4​​=14×10−3×136=1.9gm [OH−]=10028​=0.28M

$1.9 g, 0.14 m o l L^{- 1}$

$13.6 g, 0.14 m o l L^{- 1}$

$1.9 g, 0.28 m o l L^{- 1}$

$13.6 g, 0.28 m o l L^{- 1}$

$w_{C a S O_{4}} = 14 \times 1 0^{- 3} \times 136 = 1.9 g m$
$[O H^{-}] = \frac{28}{100} = 0.28 M$