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Question
Chemistry
A mixture having 2 g of hydrogen and 32 g of oxygen occupies how much volume at NTP?
Q. A mixture having
2
g
of hydrogen and
32
g
of oxygen occupies how much volume at
NTP
?
2154
200
Some Basic Concepts of Chemistry
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A
44.8
L
51%
B
22.4
L
29%
C
11.2
L
7%
D
67.2
L
13%
Solution:
2
g
of
H
2
=
1
mole,
32
g
of
O
2
=
1
mole
Total volume of
2
moles of gases at
NTP
=
2
×
22.4
L
=
44.8
L