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Chemistry
A mixture having 2 g of hydrogen and 32 g of oxygen occupies how much volume at NTP?
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Q. A mixture having $2\, g$ of hydrogen and $32\, g$ of oxygen occupies how much volume at $NTP$?
Some Basic Concepts of Chemistry
A
$44.8\,L$
51%
B
$22.4\,L$
29%
C
$11.2\,L$
7%
D
$67.2\,L$
13%
Solution:
$2 \,g$ of $H_2 = 1$ mole, $32 \,g$ of $O_2 = 1$ mole
Total volume of $2$ moles of gases at $NTP = 2 \times 22.4 \,L$
$ = 44.8\,L$