Question

A mirror in the first quadrant is in the shape of a hyperbola whose equation is $xy=1$. A light source in the second quad rantem its a beam of light that hits the mirror at the point $(2,1/2)$. If the reflected ray is parallel to the Y-axis, the slope of the incident beam is

• A. $\frac{13}{8}$
• B. $\frac{7}{4}$
• C. $\frac{15}{8}$
• D. $2$

Answer 1

Answer: (C)

Equation of hyperbola $xy=1$

$y=\frac{1}{x}$
$\frac{dy}{dx}=\frac{-1}{x^2}$
Slope of tangent at $\left(2,\frac{1}{2}\right)$
${\left(\frac{dy}{dx}\right)}_{2,\frac{1}{2}}=\frac{-1}{2^2}=\frac{-1}{4}$
Slope of normal $=\frac{-1}{\frac{-1}{4}}=4$
Let the slope of beam of light = m
$\therefore \left|\frac{4-m}{1+4m}\right|=\left|\frac{\infty -4}{1-4\cdot \infty }\right|$
$\Rightarrow \frac{4-m}{1+4m}=\pm \frac{1}{4}$
$\Rightarrow m=\frac{15}{8}$