A metre stick weighing 600 g, is displaced through an angle of 60° in vertical plane as shown. The change in its potential energy is (g = 10 ms-2)

Question

A metre stick weighing 600 g, is displaced through an angle of 60° in vertical plane as shown. The change in its potential energy is (g = 10 ms-2) (A) 1.5 J (B) 15 J (C) 30 J (D) 45 J

Tardigrade Admin · Accepted Answer

Δ U = (MgL/2)(1-cos θ) = (600 ×10 × 1/1000 × 2)×(1/2) Δ U = (6/4) = 1.5 J

Q. A metre stick weighing $600 g$ , is displaced through an angle of $6 0^{°}$ in vertical plane as shown. The change in its potential energy is $(g = 10 m s^{- 2})$

$1.5 J$

$15 J$

$30 J$

$45 J$

$Δ U = \frac{M gL}{2} (1 - cos θ)$
$= \frac{600 \times 10 \times 1}{1000 \times 2} \times \frac{1}{2}$
$Δ U = \frac{6}{4} = 1.5 J$

Q. A metre stick weighing 600g, is displaced through an angle of 60° in vertical plane as shown. The change in its potential energy is (g=10ms−2)

1.5J

15J

30J

45J