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  4. A metre stick weighing 600 g, is displaced through an angle of 60° in vertical plane as shown. The change in its potential energy is (g = 10 ms-2)

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Q. A metre stick weighing $600\, g$, is displaced through an angle of $60^°$ in vertical plane as shown. The change in its potential energy is $(g = 10\, ms^{-2})$Physics Question Image

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Solution:

$\Delta U = \frac{MgL}{2}\left(1-cos\,\theta\right)$
$= \frac{600 \times10 \times 1}{1000 \times 2}\times\frac{1}{2}$
$\Delta U = \frac{6}{4} = 1.5\,J$