Q.
A metre rod of mass 200 g is suspended by two strings at each end as shown in figure. A body of mass 300 g is suspended by a weightless string at 30 cm mark. The tensions in the string 2 is
Solution:
The various forces acting on the metre rod are shown in figure.
Net force acting on the rod is zero.
That is,
or [ g = 10 m
= (0.3 + 0.2) 10 N = 0.5 10 N = 5 N ....(1)
Net torqure acting on the rod =
For equilibrium, net torque acting on the body is zero
i.e.
= 1 + 0.9 = 1.9 N
