A meter bridge setup is shown in the figure. It is used to determine an unknown resistance R using a given resistor of 15 Ω. The galvanometer (G) shows null deflection when tapping key is at 43 cm mark from end A. If the end correction for end A is 2 cm. then the determined value of R will be Ω.

Question

A meter bridge setup is shown in the figure. It is used to determine an unknown resistance R using a given resistor of 15 Ω. The galvanometer (G) shows null deflection when tapping key is at 43 cm mark from end A. If the end correction for end A is 2 cm. then the determined value of R will be Ω. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Using the conditions of a balanced wheat stone bridge and adding the end correction. (15/(43+2))=( R /(102-45)) ⇒ R =(57/45) × 15 R =19 Ω

Using the conditions of a balanced wheat stone bridge and adding the end correction. (43+2)15​=(102−45)R​ ⇒R=4557​×15 R=19Ω

Using the conditions of a balanced wheat stone bridge and adding the end correction.
$\frac{15}{( 43 + 2 )} = \frac{R}{( 102 - 45 )}$
$\Rightarrow R = \frac{57}{45} \times 15$
$R = 19 Ω$