A meter bridge is set-up as shown, to determine an unknown resistance ' X ' using a standard 10 ohm resistor. The galvanometer shows null point when tapping-key is at 52 cm mark. The end-corrections are 1 cm and 2 cm respectively for the ends A and B. The determined value of ' X ' is

Question

A meter bridge is set-up as shown, to determine an unknown resistance ' X ' using a standard 10 ohm resistor. The galvanometer shows null point when tapping-key is at 52 cm mark. The end-corrections are 1 cm and 2 cm respectively for the ends A and B. The determined value of ' X ' is (A) 10.2 ohm (B) 10.6 ohm (C) 10.8 ohm (D) 11.1 ohm

Tardigrade Admin · Accepted Answer

X (48+2)=(10)(52+1) X =(530/50)=10.6 Ω

Q. A meter bridge is set-up as shown, to determine an unknown resistance ' X ' using a standard 10 ohm resistor. The galvanometer shows null point when tapping-key is at 52cm mark. The end-corrections are 1cm and 2cm respectively for the ends A and B. The determined value of ' X ' is

10.2 ohm

10.6 ohm

10.8 ohm

11.1 ohm

X(48+2)=(10)(52+1) X=50530​=10.6Ω

$X (48 + 2) = (10) (52 + 1)$
$X = \frac{530}{50} = 10.6 Ω$