A metallic wire of resistance 12 Ω is bent to form a square. The resistance between two diagonal points would be

Question

A metallic wire of resistance 12 Ω is bent to form a square. The resistance between two diagonal points would be (A) 12 Ω (B) 24 Ω (C) 6 Ω (D) 3 Ω

Tardigrade Admin · Accepted Answer

When a metallic wire of resistance 12 ohm is bent to form a square, the equivalent circuit diagram is as shown in figure. <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/be843ab6e20aab6d117ad900afeeefd2-.png" /> Resistance of operatornamearm ABC =3+3=6 Ω Similarly, for operatornamearm ADC =6 Ω Their effective resistance is (6 × 6/6+6)=3 Ω

Q. A metallic wire of resistance $12 Ω$ is bent to form a square. The resistance between two diagonal points would be

$12 Ω$

$24 Ω$

$6 Ω$

$3 Ω$

When a metallic wire of resistance 12 ohm is bent to form a square, the equivalent circuit diagram is as shown in figure.

Resistance of $arm A BC = 3 + 3 = 6Ω$
Similarly, for $arm A D C = 6Ω$
Their effective resistance is $\frac{6 \times 6}{6 + 6} = 3Ω$

Q. A metallic wire of resistance 12Ω is bent to form a square. The resistance between two diagonal points would be

12Ω

24Ω

6Ω

3Ω