A metallic square loop ABCD is moving in its own plane with velocity v in a uniform magnetic field perpendicular to its plane as shown in figure. An electric field is induced

Question

A metallic square loop ABCD is moving in its own plane with velocity v in a uniform magnetic field perpendicular to its plane as shown in figure. An electric field is induced <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/337c0c2ef9b7bcd47746a98619eabbda-.jpeg" /> (A) in AD, but not in BC (B) in BC, but not in AD (C) neither in AD nor in BC (D) in both AD and BC

Tardigrade Admin · Accepted Answer

The square loop ABCD is a metallic loop. So it consists of the free electrons. When the loop moves in a magnetic field, the free electrons in the AD and BC rod will experience the Lorentz force and they will move towards the ends creating a potential difference in the rods. This induced emf leads to the electric field induced in the rods AD and BC of the square loop. But there will be no current flowing in the loop as ned potential difference is zero.

Q. A metallic square loop $A BC D$ is moving in its own plane with velocity $v$ in a uniform magnetic field perpendicular to its plane as shown in figure. An electric field is induced

in $A D$ , but not in $BC$

in $BC$ , but not in $A D$

neither in $A D$ nor in $BC$

in both $A D$ and $BC$

Q. A metallic square loop ABCD is moving in its own plane with velocity v in a uniform magnetic field perpendicular to its plane as shown in figure. An electric field is induced

in AD, but not in BC

in BC, but not in AD

neither in AD nor in BC

in both AD and BC

Q. A metallic square loop $A BC D$ is moving in its own plane with velocity $v$ in a uniform magnetic field perpendicular to its plane as shown in figure. An electric field is induced

in $A D$ , but not in $BC$

in $BC$ , but not in $A D$

neither in $A D$ nor in $BC$

in both $A D$ and $BC$