A metallic block weighs 15 N in air. It weighs 12 N when immersed in water and 13 N when immersed in another liquid. What is the specific gravity of the liquid?

Question

A metallic block weighs 15 N in air. It weighs 12 N when immersed in water and 13 N when immersed in another liquid. What is the specific gravity of the liquid? (A) 1/3 (B) 2/3 (C) 12/13 (D) 13/15

Tardigrade Admin · Accepted Answer

(σ/ρw) = (15/15 - 12') (σ/ρl) = (15/15 - 13) ⇒ (ρl/ρw) = (2/3)

Q. A metallic block weighs $15 N$ in air. It weighs $12 N$ when immersed in water and $13 N$ when immersed in another liquid. What is the specific gravity of the liquid?

$1/3$

$2/3$

$12/13$

$13/15$

$\frac{σ}{ρ _{w}} = \frac{15}{15 - 1 2 ^{'}}$
$\frac{σ}{ρ _{l}} = \frac{15}{15 - 13}$
$\Rightarrow \frac{ρ _{l}}{ρ _{w}} = \frac{2}{3}$

Q. A metallic block weighs 15N in air. It weighs 12N when immersed in water and 13N when immersed in another liquid. What is the specific gravity of the liquid?

1/3

2/3

12/13

13/15