A metal surface of work function 1.07 eV is irradiated with light of wavelength 332 nm. The retarding potential required to stop the escape of photo-electrons is

Question

A metal surface of work function 1.07 eV is irradiated with light of wavelength 332 nm. The retarding potential required to stop the escape of photo-electrons is (A) 4.81 eV (B) 3.74 eV (C) 2.66 eV (D) 1.07 eV

Tardigrade Admin · Accepted Answer

Energy of incident light E(e V)=(12375/3320) =3.65 Volt (332 nm =3320 mathringA) According to the relation E=W0+e V0 ⇒ V0=((E-W0)/e) =(3.72 e V-1.07 e V/e) =2.65 Volt.

Q. A metal surface of work function $1.07 e V$ is irradiated with light of wavelength $332 nm$ . The retarding potential required to stop the escape of photo-electrons is

4.81 eV

3.74 eV

2.66 eV

1.07 eV

Energy of incident light $E (e V) = \frac{12375}{3320}$
$= 3.65$ Volt
$(332 nm = 3320 \overset{˚}{A})$
According to the relation $E = W_{0} + e V_{0}$
$\Rightarrow V_{0} = \frac{( E - W _{0} )}{e}$
$= \frac{3.72 e V - 1.07 e V}{e}$
$= 2.65$ Volt.

Q. A metal surface of work function 1.07eV is irradiated with light of wavelength 332nm. The retarding potential required to stop the escape of photo-electrons is