A metal surface of work function 1.07 eV is irradiated with light of wavelength 332 nm . The retarding potential required to stop the escape of photoelectrons is

Question

A metal surface of work function 1.07 eV is irradiated with light of wavelength 332 nm . The retarding potential required to stop the escape of photoelectrons is (A) 1.07eV (B) 2.66eV (C) 3.7 eV (D) 4.81eV

Tardigrade Admin · Accepted Answer

Retarding potential, Vs=(h c/λ e)-(φ0/e)=(1240 × 10- 9/330 × 10- 9)-1.07 =3.73-1.07=2.66 V

Q. A metal surface of work function $1.07 e V$ is irradiated with light of wavelength $332 nm$ . The retarding potential required to stop the escape of photoelectrons is

$1.07 e V$

$2.66 e V$

$3.7 e V$

$4.81 e V$

Retarding potential,
$V_{s} = \frac{h c}{λ e} - \frac{ϕ _{0}}{e} = \frac{1240 \times 1 0 ^{- 9}}{330 \times 1 0 ^{- 9}} - 1.07$
$= 3.73 - 1.07 = 2.66 V$

Q. A metal surface of work function 1.07eV is irradiated with light of wavelength 332nm . The retarding potential required to stop the escape of photoelectrons is

1.07eV

2.66eV

3.7eV

4.81eV