A metal rod of resistance 20 Ω is fixed along , a diameter of a conducting ring of radius 0.1 m and lies on x - y plane. There is a magnetic field barB = (50 T) hatk . The ring rotates with an angular velocity ω=20 rad / s about its axis. An external resistance of 10 Ω is connected across the centre of the ring and rim. The current through external through external resistance is :

Question

A metal rod of resistance 20 Ω is fixed along , a diameter of a conducting ring of radius 0.1 m and lies on x - y plane. There is a magnetic field barB = (50 T) hatk . The ring rotates with an angular velocity ω=20 rad / s about its axis. An external resistance of 10 Ω is connected across the centre of the ring and rim. The current through external through external resistance is : (A) (1/4)A (B) (1/2)A (C) (1/3)A (D) Zero

Tardigrade Admin · Accepted Answer

emf induced between centre of the ring and the rim is e = (1/2) B ω R2 = (1/2) (50 )(20)(20)2 = 5V Now the circuit can be drawn as follows: ∴ i = (5/10 +5) = (1/3)A

$\frac{1}{4} A$

$\frac{1}{2} A$

$\frac{1}{3} A$

Zero

emf induced between centre of the ring and the rim is
$e = \frac{1}{2} B ω R^{2} = \frac{1}{2} (50) (20) (20)^{2}$ = 5V
Now the circuit can be drawn as follows :
$∴ i = \frac{5}{10 + 5} = \frac{1}{3} A$

41​A

21​A

31​A

Zero

emf induced between centre of the ring and the rim is e=21​BωR2=21​(50)(20)(20)2 = 5V Now the circuit can be drawn as follows : ∴i=10+55​=31​A

$\frac{1}{4} A$

$\frac{1}{2} A$

$\frac{1}{3} A$

emf induced between centre of the ring and the rim is
$e = \frac{1}{2} B ω R^{2} = \frac{1}{2} (50) (20) (20)^{2}$ = 5V
Now the circuit can be drawn as follows :
$∴ i = \frac{5}{10 + 5} = \frac{1}{3} A$