A metal rod of length 2 m is rotating with an angular velocity of 100 rad / s in a plane perpendicular to a uniform magnetic field of 0.3 T. The potential difference between the ends of the rod is

Question

A metal rod of length 2 m is rotating with an angular velocity of 100 rad / s in a plane perpendicular to a uniform magnetic field of 0.3 T. The potential difference between the ends of the rod is (A) 30 V (B) 40 V (C) 60 V (D) 600 V

Tardigrade Admin · Accepted Answer

e=(1/2) B l2 ω=(1/2) × 0.3 ×(2)2 × 100=60 V

Q. A metal rod of length $2 m$ is rotating with an angular velocity of $100 r a d / s$ in a plane perpendicular to a uniform magnetic field of $0.3 T$ . The potential difference between the ends of the rod is

30 V

40 V

60 V

600 V

$e = \frac{1}{2} B l^{2} ω = \frac{1}{2} \times 0.3 \times (2)^{2} \times 100 = 60 V$

Q. A metal rod of length 2m is rotating with an angular velocity of 100rad/s in a plane perpendicular to a uniform magnetic field of 0.3T. The potential difference between the ends of the rod is