A metal M of equivalent mass E forms an oxide of molecular formula Mx Oy. The atomic mass of the metal is given by the correct equation

Question

A metal M of equivalent mass E forms an oxide of molecular formula Mx Oy. The atomic mass of the metal is given by the correct equation (A) 2E ( (y/x) ) (B) xyE (C) E / y (D) y / E

Tardigrade Admin · Accepted Answer

Let the atomic mass of metal, 'M' = a
Given, equivalent mass of metal, M = E

x M + y O \to M_{x} O_{y}

∴

'xa' g metal 'M' reacts with oxygen = 16y g,
According to law of chemical equivalents

w \propto E

\frac{w _{1}}{w _{2}} = \frac{E _{1}}{E _{2}}

\frac{x a}{16 y} = \frac{E}{8}

a = 2 E (\frac{y}{x})

Q. A metal M of equivalent mass E forms an oxide of molecular formula $M_{x} O_{y}$ . The atomic mass of the metal is given by the correct equation

$2 E (\frac{y}{x})$

xyE

E / y

y / E

Q. A metal M of equivalent mass E forms an oxide of molecular formula Mx​Oy​. The atomic mass of the metal is given by the correct equation

2E(xy​)

xyE

E / y

y / E

Let the atomic mass of metal, 'M' = a Given, equivalent mass of metal, M = E xM+yO→Mx​Oy​ ∴ 'xa' g metal 'M' reacts with oxygen = 16y g, According to law of chemical equivalents w∝E w2​w1​​=E2​E1​​ 16yxa​=8E​ a=2E(xy​)

Q. A metal M of equivalent mass E forms an oxide of molecular formula $M_{x} O_{y}$ . The atomic mass of the metal is given by the correct equation

$2 E (\frac{y}{x})$