A metal M forms hexagonal close-packed structure. The total number of voids in 0.02 mol of it is × 1021 (Nearest integer) (. Given .NA=6.02 × 1023)

Question

A metal M forms hexagonal close-packed structure. The total number of voids in 0.02 mol of it is × 1021 (Nearest integer) (. Given .NA=6.02 × 1023) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

One unit cell of hep contains =18 voids No. of voids in 0.02 mol of hcp =(18/6) × 6.02 × 1023 × 0.02 ≈ 3.6 × 1022 ≈ 36 × 1021

Q. A metal $M$ forms hexagonal close-packed structure. The total number of voids in $0.02 m o l$ of it is ____ $\times 1 0^{21}$ (Nearest integer)
$($ Given $N_{A} = 6.02 \times 1 0^{23})$

One unit cell of hep contains $= 18$ voids
No. of voids in $0.02 m o l$ of hcp
$= \frac{18}{6} \times 6.02 \times 1 0^{23} \times 0.02$
$\approx 3.6 \times 1 0^{22}$
$\approx 36 \times 1 0^{21}$

Q. A metal M forms hexagonal close-packed structure. The total number of voids in 0.02mol of it is ____×1021 (Nearest integer) ( Given NA​=6.02×1023)

One unit cell of hep contains =18 voids No. of voids in 0.02mol of hcp =618​×6.02×1023×0.02 ≈3.6×1022 ≈36×1021

Q. A metal $M$ forms hexagonal close-packed structure. The total number of voids in $0.02 m o l$ of it is ____ $\times 1 0^{21}$ (Nearest integer)
$($ Given $N_{A} = 6.02 \times 1 0^{23})$

One unit cell of hep contains $= 18$ voids
No. of voids in $0.02 m o l$ of hcp
$= \frac{18}{6} \times 6.02 \times 1 0^{23} \times 0.02$
$\approx 3.6 \times 1 0^{22}$
$\approx 36 \times 1 0^{21}$