A metal crystallizes with a face-centered cubic lattice. The edge of the unit cell is 408 pm. The diameter of the metal atom is

Question

A metal crystallizes with a face-centered cubic lattice. The edge of the unit cell is 408 pm. The diameter of the metal atom is (A) 144 pm (B) 204 pm (C) 288 pm (D) 408 pm

Tardigrade Admin · Accepted Answer

For FCC r =( a /2 √2) So diameter =(a/√2)=(408/1.414)=288.5 pm

Q. A metal crystallizes with a face-centered cubic lattice. The edge of the unit cell is $408 p m$ . The diameter of the metal atom is

144 pm

204 pm

288 pm

408 pm

For $FCC r = \frac{a}{2 2}$

So diameter $= \frac{a}{2} = \frac{408}{1.414} = 288.5 p m$

Q. A metal crystallizes with a face-centered cubic lattice. The edge of the unit cell is 408pm. The diameter of the metal atom is