Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Physics
A metal ball of surface area 400 cm 2 and temperature 627° C is surrounded by a vessel at 27° C. If the emissivity of the metal is 0.7 , then the rate of loss of heat from the ball is (σ=5.67 × 10-8 J / m -2- s - k 4)
Q. A metal ball of surface area
400
c
m
2
and temperature
62
7
∘
C
is surrounded by a vessel at
2
7
∘
C
. If the emissivity of the metal is 0.7 , then the rate of loss of heat from the ball is
(
σ
=
5.67
×
1
0
−
8
J
/
m
−
2
−
s
−
k
4
)
5715
217
Thermal Properties of Matter
Report Error
A
1100
J
/
s
26%
B
1579.7
J
/
s
18%
C
1469.6
J
/
s
41%
D
1290
J
/
s
15%
Solution:
A
×
t
E
=
σ
(
T
4
−
T
o
4
)
[
T
=
627
+
273
=
900
]
[
T
o
=
27
+
273
=
300
]
⇒
t
E
=
σ
A
(
T
4
−
T
o
4
)
P
=
5.67
×
1
0
−
8
×
400
×
1
0
−
4
[
(
900
)
4
−
(
300
)
4
]
P
=
5.67
×
1
0
−
8
×
4
×
1
0
−
2
[
6561
×
1
0
8
−
81
×
1
0
8
]
P
=
22.68
×
6480
×
1
0
−
2
=
1469.6
J
/
S