A mass of 10 kg is suspended from a spring balance. It is pulled aside by a horizontal string so that it makes an angle of 60° with the vertical. The new reading of the balance is

Question

A mass of 10 kg is suspended from a spring balance. It is pulled aside by a horizontal string so that it makes an angle of 60° with the vertical. The new reading of the balance is (A) 20 kg.wt (B) 10 kg.wt (C) 10 √ 3 kg.wt  (D) 20 √ 3 kg.wt

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/9f0ff82aa7cd27af35bc0bafac3b190e-.png" /> The situation is shown in figure At an angle of 60°, T cos θ =m g T =(m g/ cos θ)=(10 g/ cos 60°) =(10/1 / 2) kg - wt . =20 kg - wt

Q. A mass of $10 k g$ is suspended from a spring balance. It is pulled aside by a horizontal string so that it makes an angle of $6 0^{\circ}$ with the vertical. The new reading of the balance is

$20 k g . wt$

$10 k g . wt$

$103 k g . wt$

$203 k g . wt$

The situation is shown in figure At an angle of $6 0^{\circ}$ ,
$T cos θ = m g$
$T = \frac{m g}{c o s θ} = \frac{10 g}{c o s 6 0 ^{\circ}}$
$= \frac{10}{1/2} k g - wt .$
$= 20 k g - wt$

Q. A mass of 10kg is suspended from a spring balance. It is pulled aside by a horizontal string so that it makes an angle of 60∘ with the vertical. The new reading of the balance is

20kg.wt

10kg.wt

103​kg.wt

203​kg.wt