A mass of 10 g moving horizontally with a velocity of 100 cm/s strikes a pendulum bob of mass 10 g. The two masses stick together. The maximum height reached by the system now is (.g = 10 m/s2)

Question

A mass of 10 g moving horizontally with a velocity of 100 cm/s strikes a pendulum bob of mass 10 g. The two masses stick together. The maximum height reached by the system now is (.g = 10 m/s2) (A) zero (B) 5 cm (C) 2.5cm (D) 1.25cm

Tardigrade Admin · Accepted Answer

m1=10 text g, text v=100 text cm/s m1+m2=20 text g, text h=? g=10 text m/s2=1000 text cm/s2 From law of conservation of energy (1/2)mv2=(m1+m2)gh ⇒ h=(m1v12/2(m1+m2)g) ∴ h=(10× 100× 100/2× 20× 1000) h=2.5 text cm.

Q. A mass of 10 g moving horizontally with a velocity of 100 cm/s strikes a pendulum bob of mass 10 g. The two masses stick together. The maximum height reached by the system now is (.g = 10 m/s2)

zero

5 cm

2.5cm

1.25cm

m1​=10g,v=100cm/s m1​+m2​=20g,h=? g=10m/s2=1000cm/s2 From law of conservation of energy 21​mv2=(m1​+m2​)gh ⇒ h=2(m1​+m2​)gm1​v12​​ ∴ h=2×20×100010×100×100​ h=2.5cm.