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  4. A mass of 10 g moving horizontally with a velocity of 100 cm/s strikes a pendulum bob of mass 10 g. The two masses stick together. The maximum height reached by the system now is (.g = 10 m/s2)

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Q. A mass of 10 g moving horizontally with a velocity of 100 cm/s strikes a pendulum bob of mass 10 g. The two masses stick together. The maximum height reached by the system now is (.g = 10 m/s2)Physics Question Image

MGIMS WardhaMGIMS Wardha 2011

Solution:

$ {{m}_{1}}=10\text{ }g,\text{ }v=100\text{ }cm/s $ $ {{m}_{1}}+{{m}_{2}}=20\text{ }g,\text{ }h=? $ $ g=10\text{ }m/{{s}^{2}}=1000\text{ }cm/{{s}^{2}} $ From law of conservation of energy $ \frac{1}{2}m{{v}^{2}}=({{m}_{1}}+{{m}_{2}})gh $ $ \Rightarrow $ $ h=\frac{{{m}_{1}}v_{1}^{2}}{2({{m}_{1}}+{{m}_{2}})g} $ $ \therefore $ $ h=\frac{10\times 100\times 100}{2\times 20\times 1000} $ $ h=2.5\text{ }cm. $