Q.
A mass of 1kg is acted upon by a single force F→=(4i^+4j^)N . Due to force, mass is displaced from (0,0) to (1m,1m) . If initially, the speed of the particle was 2ms−1 , its final speed should approximately be
2275
200
NTA AbhyasNTA Abhyas 2020Motion in a Plane
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Solution:
Mass is displaced from (0, 0) to (1, 1). Therefore displacement is, S→=(1−0)i^+(1−0)j^ S→=(i^+j^)m
Given force F→=(4i^+4j^)N ∴ Work done by a constant force, W=F→.S→ W=(4i^+4j^).(i^+j^) W=4+4=8J
From work-energy theorem ΔK=W 21m(ν22−ν12)=W 21(1)(ν22−22)=8 ν22=20 ν2=4.5ms−1