Question

A mass $M$ of $100kg$ is suspended with the use of strings $A,B$ and $C$ as shown in the figure, where $W$ is the vertical wall and $R$ is a rigid horizontal rod. The tension in the string $B$ is

• A. $100gN$
• B. zero
• C. $100\sqrt{2}gN$
• D. $\frac{100}{\sqrt{2}}gN$

Answer 1

Answer: (A)

Let $T$ be the tension in the string $C$. Then in equilibrium,
$T\sin 45^{\circ }=Mg$
$T\cos 45^{\circ }=\text{ tension in }B$
Hence, tension in $B=\frac{Mg}{\tan 45^{\circ }}$
$=Mg=100gN$