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  4. A mass M of 100 kg is suspended with the use of strings A, B and C as shown in the figure, where W is the vertical wall and R is a rigid horizontal rod. The tension in the string B is <img class=img-fluid question-image alt=image src=https://cdn.tardigrade.in/img/question/physics/429fb8acfcf68b1659fcbfbfd0bdadc5-.png />

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Q. A mass $M$ of $100 \,kg$ is suspended with the use of strings $A, B$ and $C$ as shown in the figure, where $W$ is the vertical wall and $R$ is a rigid horizontal rod. The tension in the string $B$ is
image

Laws of Motion

Solution:

Let $T$ be the tension in the string $C$. Then in equilibrium,
$T \sin 45^{\circ}=M g $
$T \cos 45^{\circ}=\text { tension in } B$
Hence, tension in $B=\frac{M g}{\tan 45^{\circ}}$
$=M g=100\, g N$
image