Question

A mass $\text{M}$ of $100\text{kg}$ is suspended with the use of strings $\text{A},\text{B}$ and $\text{C}$ as shown in the figure, where $\text{W}$ is the vertical wall and $\text{R}$ is a rigid horizontal rod. The tension in the string $\text{B}$ is

• A. $100\text{g}N$
• B. Zero
• C. $100\sqrt{2}\text{g}\text{ N}$
• D. $\frac{100}{\sqrt{2}}\text{g N}$

Answer 1

Answer: (A)

Let $\text{T}$ be the tension in the string $\text{C}$ . Hence

$\text{T}\text{cos}45^{\circ }=Mg$
$Tsin45^{\circ }=$ tension in $B$
Hence, tension in $\text{B}=\text{M}\text{g}=100\text{g}\text{N}$