Q.
A mass M is split into two parts, m0 and M−m0. These two masses are then separated by a distance D. If the gravitational force between the parts is maximum, then the ratio Mm0 is
According to given situation,
Again, m0 and M−m0 are kept at a distance D gravitational force, F=D2Gm0(M−m0) F will be maximum, when dm0dF=0 ⇒dm0dD2Gm0(M−m0)=0 ⇒dm0d(D2Gm0M−Gm02)=0 ⇒D2GM−2Gm0=0 ⇒GM−2Gm0=0 ⇒M−2m0=0 ⇒2m0=M ⇒Mm0=21=0.5