A mass m is attached to a thin wire and whirled in a vertical circle. The wire is most likely to break when:

Question

A mass m is attached to a thin wire and whirled in a vertical circle. The wire is most likely to break when: (A) the mass is at the lowest point (B) inclined at an angle of 60° from vertical (C) the mass is at the highest point (D) the wire is horizontal

Tardigrade Admin · Accepted Answer

T -mg = (mu2/I) T =mg + (mu2/I) The tension is maximum at the lowest position of mass, so the chance of breaking is maximum.

Q. A mass $m$ is attached to a thin wire and whirled in a vertical circle. The wire is most likely to break when:

the mass is at the lowest point

inclined at an angle of $6 0^{\circ}$ from vertical

the mass is at the highest point

the wire is horizontal

$T - m g = \frac{m u ^{2}}{I}$
$T = m g + \frac{m u ^{2}}{I}$
The tension is maximum at the lowest position of mass, so the chance of breaking is maximum.

Q. A mass m is attached to a thin wire and whirled in a vertical circle. The wire is most likely to break when: