A mass m hangs with the help of a string wrapped around a pulley on a frictionless bearing. The pulley has mass m and radius R. Assuming pulley to be a perfect uniform circular disc, the acceleration of the mass m, if the string does not slip on the pulley, is

Question

A mass m hangs with the help of a string wrapped around a pulley on a frictionless bearing. The pulley has mass m and radius R. Assuming pulley to be a perfect uniform circular disc, the acceleration of the mass m, if the string does not slip on the pulley, is (A) (g/3) (B) (3/2) g (C) g (D) (2/3) g

Tardigrade Admin · Accepted Answer

a=(m g/m+(I)R2)=(m g/m+(m)2)=(2 g/3)

Q. A mass $m$ hangs with the help of a string wrapped around a pulley on a frictionless bearing. The pulley has mass $m$ and radius $R$ . Assuming pulley to be a perfect uniform circular disc, the acceleration of the mass $m$ , if the string does not slip on the pulley, is

$\frac{g}{3}$

$\frac{3}{2} g$

$g$

$\frac{2}{3} g$

$a = \frac{m g}{m + \frac{I}{R ^{2}}} = \frac{m g}{m + \frac{m}{2}} = \frac{2 g}{3}$

Q. A mass m hangs with the help of a string wrapped around a pulley on a frictionless bearing. The pulley has mass m and radius R. Assuming pulley to be a perfect uniform circular disc, the acceleration of the mass m, if the string does not slip on the pulley, is

3g​

23​g

g

32​g

a=m+R2I​mg​=m+2m​mg​=32g​

Q. A mass $m$ hangs with the help of a string wrapped around a pulley on a frictionless bearing. The pulley has mass $m$ and radius $R$ . Assuming pulley to be a perfect uniform circular disc, the acceleration of the mass $m$ , if the string does not slip on the pulley, is

$\frac{g}{3}$

$\frac{3}{2} g$

$g$

$\frac{2}{3} g$

$a = \frac{m g}{m + \frac{I}{R ^{2}}} = \frac{m g}{m + \frac{m}{2}} = \frac{2 g}{3}$