A mass is whirled in a circular path with constant angular velocity and its angular momentum is L . If the string is now halved keeping the angular velocity the same, the angular momentum is

Question

A mass is whirled in a circular path with constant angular velocity and its angular momentum is L . If the string is now halved keeping the angular velocity the same, the angular momentum is (A) ( textL/4) (B) ( textL/2) (C) L (D) 2L

Tardigrade Admin · Accepted Answer

L = mr2 &omega;. For given m and &omega;, L &prop; r2. If r is halved, the angular momentum L becomes one-fourth.

Q. A mass is whirled in a circular path with constant angular velocity and its angular momentum is $L$ . If the string is now halved keeping the angular velocity the same, the angular momentum is

$\frac{L}{4}$

$\frac{L}{2}$

$L$

$2 L$

L = mr² ω. For given m and ω, L ∝ r². If r is halved, the angular momentum L becomes one-fourth.

Q. A mass is whirled in a circular path with constant angular velocity and its angular momentum is L . If the string is now halved keeping the angular velocity the same, the angular momentum is

4L​

2L​

L

2L

L = mr2 ω. For given m and ω, L ∝ r2. If r is halved, the angular momentum L becomes one-fourth.

Q. A mass is whirled in a circular path with constant angular velocity and its angular momentum is $L$ . If the string is now halved keeping the angular velocity the same, the angular momentum is

$\frac{L}{4}$

$\frac{L}{2}$

$L$

$2 L$

L = mr² ω. For given m and ω, L ∝ r². If r is halved, the angular momentum L becomes one-fourth.