Question

A mass is whirled in a circular path with constant angular velocity and its angular momentum is $L$ . If the string is now halved keeping the angular velocity the same, the angular momentum is

• A. $\frac{\text{L}}{4}$
• B. $\frac{\text{L}}{2}$
• C. $L$
• D. $2L$

Answer 1

Answer: (A)

L = mr² ω. For given m and ω, L ∝ r². If r is halved, the angular momentum L becomes one-fourth.