As shown in the figure at point O a mass is performing vertical circular motion. The average velocity of the particle is increased, then at which point will the string break

Question

As shown in the figure at point O a mass is performing vertical circular motion. The average velocity of the particle is increased, then at which point will the string break (A) A (B) B (C) C (D) D

Tardigrade Admin · Accepted Answer

When a sphere is rotating in a vertical circle,
it exerts the maximum outward pull when it is at the lowest point

B

.
Therefore, tension at

B

is maximum = Weight

+ \frac{m v ^{2}}{R}

So, the string breaks at point B.

Q. As shown in the figure at point O a mass is performing vertical circular motion. The average velocity of the particle is increased, then at which point will the string break

A

B

C

D

When a sphere is rotating in a vertical circle, it exerts the maximum outward pull when it is at the lowest point B. Therefore, tension at B is maximum = Weight +Rmv2​ So, the string breaks at point B.

Q. As shown in the figure at point $O$ a mass is performing vertical circular motion. The average velocity of the particle is increased, then at which point will the string break

When a sphere is rotating in a vertical circle,
it exerts the maximum outward pull when it is at the lowest point $B$ .
Therefore, tension at $B$ is maximum = Weight $+ \frac{m v ^{2}}{R}$
So, the string breaks at point B.