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Q. As shown in the figure at point $O$ a mass is performing vertical circular motion. The average velocity of the particle is increased, then at which point will the string breakPhysics Question Image

AIPMTAIPMT 2000System of Particles and Rotational Motion

Solution:

When a sphere is rotating in a vertical circle,
it exerts the maximum outward pull when it is at the lowest point $B$.
Therefore, tension at $B$ is maximum = Weight $+\frac{mv^2}{R}$
So, the string breaks at point B.