A marble going at a speed of 2 ms -1 hits another marble of equal mass at rest. If the collision is perfectly elastic. The velocity of the first after collision is

Question

A marble going at a speed of 2 ms -1 hits another marble of equal mass at rest. If the collision is perfectly elastic. The velocity of the first after collision is (A) 4 ms -1 (B) 0 ms -1 (C) 2 ms -1 (D) 3 ms -1

Tardigrade Admin · Accepted Answer

v1=((m1-m2/m1+m2)) u1+((2 m2 u2/m1+m2))

Q. A marble going at a speed of $2 m s^{- 1}$ hits another marble of equal mass at rest. If the collision is perfectly elastic. The velocity of the first after collision is

$4 m s^{- 1}$

$0 m s^{- 1}$

$2 m s^{- 1}$

$3 m s^{- 1}$

$v_{1} = (\frac{m _{1} - m _{2}}{m _{1} + m _{2}}) u_{1} + (\frac{2 m _{2} u _{2}}{m _{1} + m _{2}})$

Q. A marble going at a speed of 2ms−1 hits another marble of equal mass at rest. If the collision is perfectly elastic. The velocity of the first after collision is

4ms−1

0ms−1

2ms−1

3ms−1