A man weighs 80 kg on earth surface. The height above ground where he will weigh 40 kg, is: (radius of earth is 6400 km)

Question

A man weighs 80 kg on earth surface. The height above ground where he will weigh 40 kg, is: (radius of earth is 6400 km) (A) 0.31 times r (B) 0.41 times r (C) 0.51 times r (D) 0.61 times r

Tardigrade Admin · Accepted Answer

w=(w/( 1+(h)r )2) ⇒ 40=(80/( 1+(h)r )2) ⇒ h=0.41 r

Q. A man weighs 80 kg on earth surface. The height above ground where he will weigh 40 kg, is: (radius of earth is 6400 km)

0.31 times r

0.41 times r

0.51 times r

0.61 times r

0.82 times r

$w = \frac{w}{( 1 + \frac{h}{r} ) ^{2}}$ $\Rightarrow$ $40 = \frac{80}{( 1 + \frac{h}{r} ) ^{2}}$ $\Rightarrow$ $h = 0.41 r$