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Physics
A man weighs 80 kg on earth surface. The height above ground where he will weigh 40 kg, is: (radius of earth is 6400 km)
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Q. A man weighs 80 kg on earth surface. The height above ground where he will weigh 40 kg, is: (radius of earth is 6400 km)
KEAM
KEAM 2003
Gravitation
A
0.31 times r
16%
B
0.41 times r
51%
C
0.51 times r
24%
D
0.61 times r
10%
E
0.82 times r
10%
Solution:
$ w=\frac{w}{{{\left( 1+\frac{h}{r} \right)}^{2}}} $ $ \Rightarrow $ $ 40=\frac{80}{{{\left( 1+\frac{h}{r} \right)}^{2}}} $ $ \Rightarrow $ $ h=0.41\,r $