A man weighing 100 kg slides down a light rope with an acceleration of 1.8 ms -2. If g=9.8 ms -2, the tension of the rope is

Question

A man weighing 100 kg slides down a light rope with an acceleration of 1.8 ms -2. If g=9.8 ms -2, the tension of the rope is (A) 180 N (B) 1160 N (C) 800 N (D) weightlessness

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/318498ebbc5db50c1a30634bdb91acb6-.png" /> The resultant of tension and weight given acceleration to the man, hence m g-T=m a ⇒ T=m g-m a=m(g-a) Given, m=100 kg g=9.8 m / s 2, a=1.8 ms -2 ∴ T=100(9.8-1.8)=800 N

Q. A man weighing $100 k g$ slides down a light rope with an acceleration of $1.8 m s^{- 2}$ . If $g = 9.8 m s^{- 2}$ , the tension of the rope is

$180 N$

$1160 N$

$800 N$

weightlessness

The resultant of tension and weight given acceleration to the man, hence
$m g - T = ma$
$\Rightarrow T = m g - ma = m (g - a)$
Given, $m = 100 k g$
$g = 9.8 m / s^{2}, a = 1.8 m s^{- 2}$
$∴ T = 100 (9.8 - 1.8) = 800 N$

Q. A man weighing 100kg slides down a light rope with an acceleration of 1.8ms−2. If g=9.8ms−2, the tension of the rope is

180N

1160N

800N