A man starts walking from the point P (-3,4), touches the x-axis at R, and then turns to reach at the point Q (0,2). The man is walking at a constant speed. If the man reaches the point Q in the minimum time, then 50(( PR )2+( RQ )2) is equal to

Question

A man starts walking from the point P (-3,4), touches the x-axis at R, and then turns to reach at the point Q (0,2). The man is walking at a constant speed. If the man reaches the point Q in the minimum time, then 50(( PR )2+( RQ )2) is equal to  (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/mathematics/763bb2ce7e3b67f583aff157a182a47e-.png" /> 50( PR 2+ RQ 2) 50(20+5) 50(25) =1250

Q. A man starts walking from the point $P (- 3, 4)$ , touches the $x$ -axis at $R$ , and then turns to reach at the point $Q (0, 2)$ . The man is walking at a constant speed. If the man reaches the point $Q$ in the minimum time, then $50 ((PR)^{2} + (RQ)^{2})$ is equal to ____

$50 (P R^{2} + R Q^{2})$
$50 (20 + 5)$
$50 (25)$
$= 1250$

Q. A man starts walking from the point P(−3,4), touches the x-axis at R, and then turns to reach at the point Q(0,2). The man is walking at a constant speed. If the man reaches the point Q in the minimum time, then 50((PR)2+(RQ)2) is equal to ____

50(PR2+RQ2) 50(20+5) 50(25) =1250

Q. A man starts walking from the point $P (- 3, 4)$ , touches the $x$ -axis at $R$ , and then turns to reach at the point $Q (0, 2)$ . The man is walking at a constant speed. If the man reaches the point $Q$ in the minimum time, then $50 ((PR)^{2} + (RQ)^{2})$ is equal to ____

$50 (P R^{2} + R Q^{2})$
$50 (20 + 5)$
$50 (25)$
$= 1250$