Question

A man standing on the road has to hold his umbrella at 30 degrees from the vertical direction to keep the rain away. He thrown away the umbrella and starts running at $10km{h}^{-1}$, he finds that the rain drops are hitting him vertically. The speed of the rain drops w.r.t. the road is

• A. $\frac{10}{\sqrt{3}}$
• B. 10
• C. $10\sqrt{3}$
• D. 20

Answer 1

Answer: (D)

From equation of relative motion

${\overrightarrow{V}}_{RM}+{\overrightarrow{V}}_{MG}={\overrightarrow{V}}_{RG}$
$\frac{|{\overrightarrow{V}}_{MG}|}{\sin \gamma }=\frac{|{\overrightarrow{V}}_{RG}|}{\sin \beta }=\frac{|{\overrightarrow{V}}_{RG}|}{\sin (\pi -\alpha )}$
According to question,
$|{\overrightarrow{V}}_{MG}|=10km{h}^{-1},\beta =90^{\circ }$
$\therefore \frac{|{\overrightarrow{V}}_{MG}|}{\sin 30^{\circ }}=\frac{{\overrightarrow{V}}_{RG}}{\sin \beta }\Rightarrow V_{RG}=20km{h}^{-1}$