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Tardigrade
Question
Physics
A man of 80 kg attempts to jump from a small boat of mass 40 kg on to the shore. He can generate a relative velocity of 6 m s- 1 between himself and the boat. His velocity towards the shore is
Q. A man of
80
k
g
attempts to jump from a small boat of mass
40
k
g
on to the shore. He can generate a relative velocity of
6
m
s
−
1
between himself and the boat. His velocity towards the shore is
3576
204
NTA Abhyas
NTA Abhyas 2020
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A
4
m
s
−
1
B
8
m
s
−
1
C
2
m
s
−
1
D
3
m
s
−
1
Solution:
Let the velocity of boat be
V
opposite to the man. By momentum conservation,
−
40
V
+
80
(
6
−
V
)
=
0
∴
V
=
4
m
s
−
1
∴
Velocity of the man
=
6
−
4
=
2
m
s
−
1