A man of 60 kg is running on the road and suddenly jumps into a stationary trolly car of mass 120 kg. Then. the trolly car starts moving with velocity 2 ms -1. The velocity of the running man was ms -1. when he jumps into the car.

Question

A man of 60 kg is running on the road and suddenly jumps into a stationary trolly car of mass 120 kg. Then. the trolly car starts moving with velocity 2 ms -1. The velocity of the running man was ms -1. when he jumps into the car. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Taking the system as man and trolley and using conservation of linear momentum. 60 × v=(60+120) × 2 ⇒ v=6 m / s

Q. A man of $60 k g$ is running on the road and suddenly jumps into a stationary trolly car of mass $120 k g$ . Then. the trolly car starts moving with velocity $2 m s^{- 1}$ . The velocity of the running man was _________ $m s^{- 1}$ . when he jumps into the car.

Taking the system as man and trolley and using conservation of linear momentum.
$60 \times v = (60 + 120) \times 2$
$\Rightarrow v = 6 m / s$

Q. A man of 60kg is running on the road and suddenly jumps into a stationary trolly car of mass 120kg. Then. the trolly car starts moving with velocity 2ms−1. The velocity of the running man was _________ms−1. when he jumps into the car.

Taking the system as man and trolley and using conservation of linear momentum. 60×v=(60+120)×2 ⇒v=6m/s

Q. A man of $60 k g$ is running on the road and suddenly jumps into a stationary trolly car of mass $120 k g$ . Then. the trolly car starts moving with velocity $2 m s^{- 1}$ . The velocity of the running man was _________ $m s^{- 1}$ . when he jumps into the car.

Taking the system as man and trolley and using conservation of linear momentum.
$60 \times v = (60 + 120) \times 2$
$\Rightarrow v = 6 m / s$