A man in a balloon throws a stone downwards with a speed of 5 m s-1 with respect to the balloon which is moving upwards with a constant acceleration of 5 ms -2. Find the magnitude of velocity (in m s-1 ) of the stone relative to the man after 2 s. (Take g=10 ms -2 )

Question

A man in a balloon throws a stone downwards with a speed of 5 m s-1 with respect to the balloon which is moving upwards with a constant acceleration of 5 ms -2. Find the magnitude of velocity (in m s-1 ) of the stone relative to the man after 2 s. (Take g=10 ms -2 ) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Initial relative velocity of stone wrt man

= 5 m s^{- 1}

relative acceleration of the stone wrt man

= (- 10) - (5) = - 15 m s^{- 2}

v = u + a t = 5 - 15 \times 2 = - 25 m s^{- 1}

Magnitude of relative velocity after

t = 2 s

is

25 m s^{- 1} ​

Q. A man in a balloon throws a stone downwards with a speed of $5 m s^{- 1}$ with respect to the balloon which is moving upwards with a constant acceleration of $5 m s^{- 2}$ . Find the magnitude of velocity (in $m s^{- 1}$ ) of the stone relative to the man after $2 s$ . (Take $g = 10 m s^{- 2}$ )

Initial relative velocity of stone wrt man $= 5 m s^{- 1}$
relative acceleration of the stone wrt man $= (- 10) - (5) = - 15 m s^{- 2}$
$v = u + a t = 5 - 15 \times 2 = - 25 m s^{- 1}$
Magnitude of relative velocity after $t = 2 s$ is $25 m s^{- 1} $

Q. A man in a balloon throws a stone downwards with a speed of 5ms−1 with respect to the balloon which is moving upwards with a constant acceleration of 5ms−2. Find the magnitude of velocity (in ms−1 ) of the stone relative to the man after 2s. (Take g=10ms−2 )

Initial relative velocity of stone wrt man =5ms−1 relative acceleration of the stone wrt man =(−10)−(5)=−15ms−2 v=u+at=5−15×2=−25ms−1 Magnitude of relative velocity after t=2s is 25ms−1​

Q. A man in a balloon throws a stone downwards with a speed of $5 m s^{- 1}$ with respect to the balloon which is moving upwards with a constant acceleration of $5 m s^{- 2}$ . Find the magnitude of velocity (in $m s^{- 1}$ ) of the stone relative to the man after $2 s$ . (Take $g = 10 m s^{- 2}$ )

Initial relative velocity of stone wrt man $= 5 m s^{- 1}$
relative acceleration of the stone wrt man $= (- 10) - (5) = - 15 m s^{- 2}$
$v = u + a t = 5 - 15 \times 2 = - 25 m s^{- 1}$
Magnitude of relative velocity after $t = 2 s$ is $25 m s^{- 1} $