A man grows into a giant such that his linear dimensions increase by a factor of 9. Assuming that his density remains same, the stress in the leg will change by a factor of :

Question

A man grows into a giant such that his linear dimensions increase by a factor of 9. Assuming that his density remains same, the stress in the leg will change by a factor of : (A) 9 (B) (1/9) (C) 81 (D) (1/81)

Tardigrade Admin · Accepted Answer

(vf/vi)=93 ∵ Density remains same So, mass propto Volume (mf/mi)=93 (( text Area ) f/( text Area )i)=92 Stress =(( text Mass ) × g/ text Area ) (σ2/σ1) =((mf/mi))((Ai/Af)) =(93/92)=9

Q. A man grows into a giant such that his linear dimensions increase by a factor of $9$ . Assuming that his density remains same, the stress in the leg will change by a factor of :

9

$\frac{1}{9}$

81

$\frac{1}{81}$

Q. A man grows into a giant such that his linear dimensions increase by a factor of 9. Assuming that his density remains same, the stress in the leg will change by a factor of :

9

91​

81

811​

vi​vf​​=93 ∵ Density remains same So, mass ∝ Volume mi​mf​​=93 ( Area )i​( Area )f​=92 Stress = Area ( Mass )×g​ σ1​σ2​​=(mi​mf​​)(Af​Ai​​) =9293​=9

Q. A man grows into a giant such that his linear dimensions increase by a factor of $9$ . Assuming that his density remains same, the stress in the leg will change by a factor of :

$\frac{1}{9}$

$\frac{1}{81}$