A man goes at the top of a smooth inclined plane. He releases a bag to fall freely and himself slides down on inclined plane to reach the bottom. If u1, and u2 are the velocities of the man and bag respectively, then

Question

A man goes at the top of a smooth inclined plane. He releases a bag to fall freely and himself slides down on inclined plane to reach the bottom. If u1, and u2 are the velocities of the man and bag respectively, then (A)  u1>u2  (B)  u1<u2  (C)  u1=u2  (D)  u1 and u2 cannot be compared

Tardigrade Admin · Accepted Answer

The gravitational force is conservative, so the work done by it is independent of path. Hence in both cases (1/2)mu2=mgh u=√2hg, independent of mass So, u1=u2

Q. A man goes at the top of a smooth inclined plane. He releases a bag to fall freely and himself slides down on inclined plane to reach the bottom. If u1, and u2 are the velocities of the man and bag respectively, then

$u_{1} > u_{2}$

$u_{1} < u_{2}$

$u_{1} = u_{2}$

$u_{1} an d u_{2} c ann o t b e co m p a re d$

The gravitational force is conservative, so the work done by it is independent of path. Hence in both cases $\frac{1}{2} m u^{2} = m g h$ $u = 2 h g,$ independent of mass So, $u_{1} = u_{2}$

Q. A man goes at the top of a smooth inclined plane. He releases a bag to fall freely and himself slides down on inclined plane to reach the bottom. If u1, and u2 are the velocities of the man and bag respectively, then

u1​>u2​

u1​<u2​

u1​=u2​

u1​andu2​cannotbecompared

The gravitational force is conservative, so the work done by it is independent of path. Hence in both cases 21​mu2=mgh u=2hg​, independent of mass So, u1​=u2​

$u_{1} > u_{2}$

$u_{1} < u_{2}$

$u_{1} = u_{2}$

$u_{1} an d u_{2} c ann o t b e co m p a re d$

The gravitational force is conservative, so the work done by it is independent of path. Hence in both cases $\frac{1}{2} m u^{2} = m g h$ $u = 2 h g,$ independent of mass So, $u_{1} = u_{2}$