A man fires a bullet of mass 200 gm at a speed of 5 m/s. The gun is of one kg mass. By what velocity the gun rebounds backward?

Question

A man fires a bullet of mass 200 gm at a speed of 5 m/s. The gun is of one kg mass. By what velocity the gun rebounds backward? (A) 1 m/s (B) 0.01 m/s (C) 0.1 m/s (D) 10 m/s

Tardigrade Admin · Accepted Answer

Mass of bullet (m1)=200 gm=0.2 kg; Speed of bullet (v1) = 5 m/sec. and mass of gun (m2) = 1 kg. Before firing, total momentum is zero. ∴ After firing total momentum is m1 v1 + m2 v2 From the law of conservation of momentum m1 v1 + m2 v2=0 or v2=(-m1v1/m2) =(-0.2×5/1) -1 m/ sec.

Q. A man fires a bullet of mass 200gm at a speed of 5m/s. The gun is of one kg mass. By what velocity the gun rebounds backward?

1 m/s

0.01 m/s

0.1 m/s

10 m/s

Q. A man fires a bullet of mass $200 g m$ at a speed of $5 m / s$ . The gun is of one $k g$ mass. By what velocity the gun rebounds backward?