Q.
A man crosses the river in minimum time of 10min with a drift of 120m. If he crosses the river in shortest path he takes 12.5min. What is his swimming speed?
For shortest time t1=vd=10⇒d=10v
and x=vRt1 120=vR10 ⇒vR=12mmin−1
For shortest path t2=v2−vR2d 12.5=v2−12210v⇒v2−122=0.8v v2−122=0.64v2 0.36v2=144 v2=400 v=20mmin−1